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## Question

primary 5 | Maths
| Angles & Geometry

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Pls help me with this

angle PQT = angle QTR = 63° (alternate angles, PQ is parallel to SR)

Angle PQS = Angle PQT - Angle SQT

= 63° - 24° = 39°

PQ = PS since all 4 sides of a rhombus are of equal length.

So triangle PQS is an isosceles triangle.

Angle PQS = Angle PSQ = 39°

(base angles of an isosceles triangle are equal)

So Angle SPQ

= 180° - 39° - 39° (angle sum of triangle SPQ)

= 102°

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