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primary 5 | Maths | Angles & Geometry
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Jovel
Jovel

primary 5 chevron_right Maths chevron_right Angles & Geometry chevron_right Singapore

Pls help me with this

Date Posted: 1 month ago
Views: 15
J
J
1 month ago
Let the point where the angle is 63° be T.

angle PQT = angle QTR = 63° (alternate angles, PQ is parallel to SR)

Angle PQS = Angle PQT - Angle SQT
= 63° - 24° = 39°


PQ = PS since all 4 sides of a rhombus are of equal length.

So triangle PQS is an isosceles triangle.

Angle PQS = Angle PSQ = 39°
(base angles of an isosceles triangle are equal)

So Angle SPQ
= 180° - 39° - 39° (angle sum of triangle SPQ)

= 102°

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AC Lim
Ac Lim's answer
2279 answers (A Helpful Person)
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Hope this helps
Jovel
Jovel
1 month ago
Thank