Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 5 | Maths
| Angles & Geometry
One Answer Below
Anyone can contribute an answer, even non-tutors.
Pls help me with this
Date Posted: 4 years ago
Views: 281
Let the point where the angle is 63° be T.
angle PQT = angle QTR = 63° (alternate angles, PQ is parallel to SR)
Angle PQS = Angle PQT - Angle SQT
= 63° - 24° = 39°
PQ = PS since all 4 sides of a rhombus are of equal length.
So triangle PQS is an isosceles triangle.
Angle PQS = Angle PSQ = 39°
(base angles of an isosceles triangle are equal)
So Angle SPQ
= 180° - 39° - 39° (angle sum of triangle SPQ)
= 102°
angle PQT = angle QTR = 63° (alternate angles, PQ is parallel to SR)
Angle PQS = Angle PQT - Angle SQT
= 63° - 24° = 39°
PQ = PS since all 4 sides of a rhombus are of equal length.
So triangle PQS is an isosceles triangle.
Angle PQS = Angle PSQ = 39°
(base angles of an isosceles triangle are equal)
So Angle SPQ
= 180° - 39° - 39° (angle sum of triangle SPQ)
= 102°
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope this helps
Date Posted:
4 years ago
Thank
360 Tutoring Program