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secondary 4 | A Maths
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Date Posted: 4 years ago
Views: 176
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done
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clear
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Done. No need to write +c for definite integrals since they will disappear during calculation anyway.
Date Posted:
4 years ago
I still can’t understand how to do
Kathy, we do the same thing as we normally do - bring up power by 1, divide by new power. The exception is, there is no c in definite integral.
Instead, using the upper and lower limits, we substitute the upper limit into the expression, lower limit into the same expression and subtract each other to obtain the value of the definite integral.
Instead, using the upper and lower limits, we substitute the upper limit into the expression, lower limit into the same expression and subtract each other to obtain the value of the definite integral.
So if you see things like
2x - ln x
after integration, with upper limit 5 and lower limit 1, the value we are interested in is
[2(5) - ln 5]
minus
[2(1) - ln 1].
2x - ln x
after integration, with upper limit 5 and lower limit 1, the value we are interested in is
[2(5) - ln 5]
minus
[2(1) - ln 1].
Pls help on that qns. Thanks
This one or the linear law one? I starting on the linear law one soon
Linear law
You can send in the next one first. Take some time to see what I did in those questions. Not all the linear law examples will contain lg or ln; sometimes it’s just simpler manipulation.
You can send the next question when you are ready, since you plan to finish integration this month
Tomorrow
I am doing other subjects so A math I putting a side first
Pls help with my qns
After 2 am; phone in bad shape
I will finish up the chapter by this week
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