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secondary 3 | A Maths
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Shan Kuek
Shan Kuek

secondary 3 chevron_right A Maths chevron_right Singapore

Help please!!

Date Posted: 3 months ago
Views: 31
snell
Snell
3 months ago
(a)
sin 300 deg
= sin (360-60) deg
= -sin 60 deg
= -√3/2


(b)
tan (-210 deg)
= tan (360 -210) deg
= tan 150 deg
= tan (180-30) deg
= -tan 30 deg
= -1/√3


(c)
cos(-π/3)
= cos π/3
= 0.5


(d)
tan 2π/3
= tan (π - 2π/3)
= -tan π/3
= -√3


...

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Eric Nicholas K
Eric Nicholas K's answer
3784 answers (Tutor Details)
1st
The first one. This gets very difficult to explain on paper. You will need to know how the Quadrants and their angles work and you also need to know the values of some trigonometric ratios (sin, cos, tan) of special angles such as 0, 30, 45, 60 and 90 (and their equivalent in radians).
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Eric Nicholas K
Eric Nicholas K's answer
3784 answers (Tutor Details)
For the second case
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Eric Nicholas K
Eric Nicholas K's answer
3784 answers (Tutor Details)
Done
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Eric Nicholas K
Eric Nicholas K's answer
3784 answers (Tutor Details)
Some useful numbers to know for special angles