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Date Posted:
1 week ago

The modulus sign is there to take into account the fact that 1/x is valid for all non-zero values of x, and therefore its integral should also be valid for negative x, but we know that the x in ln x cannot be negative, hence the modulus sign.

When we differentiate ln x, the x in ln x is in the first place only defined for x > 0, so its derivative x is also defined (at x > 0). Which is why you do not see any modulus at all during differentiation.

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Date Posted:
1 week ago