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secondary 3 | A Maths
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Date Posted: 4 years ago
Views: 248
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Date Posted:
4 years ago
Sry i don't think your answer is correct. The given answer here is 3 or 1/27
Fifth line is incorrect.
1/(log3(x)) = (log3(x))^-1, which is not the same as log3(x^(-1))
1/(log3(x)) = (log3(x))^-1, which is not the same as log3(x^(-1))
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Date Posted:
4 years ago
Thanks man
when do you need to reject, because for some question, you rejected the negative
Important is to realise that the original logarithm may not be defined. In particular, the question contains log 3 x, where x cannot be negative due to the logarithmic properties.
So, if x appears as a negative value, it would be inadmissible as a solution, since log 3 (negative number) is not defined.
So, if x appears as a negative value, it would be inadmissible as a solution, since log 3 (negative number) is not defined.
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