Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 6 | Maths
| Data Analysis
One Answer Below
Anyone can contribute an answer, even non-tutors.
help me pls
Date Posted: 5 years ago
Views: 608
let cost of 1 apple be $a
let cost of 1 pear be $b
let cost of 1 orange be $c
5c + 3a = 3.30 —(1)
4c + 6b = 3.60 —(2)
“1 apple costs 10 cents less than 1 orange” means 1 orange costs 10 cents more than 1 apple so cost of 1 orange is the sum of 10 cents and cost of 1 apple:
c = a + 0.1 —(3)
sub (3) in (2):
5(a+0.1) + 3a = 3.30
5a + 0.5 + 3a = 3.30
8a = 2.8
a=0.35
sub a=0.35 in (3):
c=0.35+0.1=0.45
sub c=0.45 in (2):
4(0.45)+6b=3.60
1.8+6b=3.6
6b=3.6-1.8
6b=1.8
b=0.3
cost of 1 pear = $b = $0.30
let cost of 1 pear be $b
let cost of 1 orange be $c
5c + 3a = 3.30 —(1)
4c + 6b = 3.60 —(2)
“1 apple costs 10 cents less than 1 orange” means 1 orange costs 10 cents more than 1 apple so cost of 1 orange is the sum of 10 cents and cost of 1 apple:
c = a + 0.1 —(3)
sub (3) in (2):
5(a+0.1) + 3a = 3.30
5a + 0.5 + 3a = 3.30
8a = 2.8
a=0.35
sub a=0.35 in (3):
c=0.35+0.1=0.45
sub c=0.45 in (2):
4(0.45)+6b=3.60
1.8+6b=3.6
6b=3.6-1.8
6b=1.8
b=0.3
cost of 1 pear = $b = $0.30
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope this helps
Date Posted:
5 years ago
360 Tutoring Program