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secondary 3 | E Maths
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Idk how to simulaneous for this i got a werid number
Date Posted: 4 years ago
Views: 448
2x + y = 1
=> y = 1 - 2x ... ... ... [1]
y = x² + 2x - 3 ... ... ... [2]
subst. [1] into [2],
=> 1 - 2x = x² + 2x - 3
*corrected*
=> x² + 4x - 4 = 0
=> x = -4.828 or 0.828
y = 1 + 9.656 or y = 1 - 1.656
y = 10.656 or -0.656
A(-4.828, 10.656) &
B(0.828, -0.656)
midpt of AB is [ (-4.828+0.828)/2 , (10.656-0.656)/2 ]
= ( -2, 5 )
=> y = 1 - 2x ... ... ... [1]
y = x² + 2x - 3 ... ... ... [2]
subst. [1] into [2],
=> 1 - 2x = x² + 2x - 3
*corrected*
=> x² + 4x - 4 = 0
=> x = -4.828 or 0.828
y = 1 + 9.656 or y = 1 - 1.656
y = 10.656 or -0.656
A(-4.828, 10.656) &
B(0.828, -0.656)
midpt of AB is [ (-4.828+0.828)/2 , (10.656-0.656)/2 ]
= ( -2, 5 )
wrong
The answer will be weird. Wait.
Sent. The coordinates are weird, but the midpoint is not. There is a reason for this.
the coordinate is not weird. is the ans.
Maybe. But I have cross-checked my answers with a graph plot from Desmond graphing calculator online.
See 1 Answer
done
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This question should be in A Maths, not E Maths.
Date Posted:
4 years ago
agreed. the coordinates of A & B r weird.
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