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primary 6 | Maths
| Geometry
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Date Posted: 4 years ago
Views: 302
a) For area of A,
Subtract the area of the inner circle from the area of square WXYZ to get the area of the 4 corners.
Each is equal to A. So divide by 4 to get your answer.
b)
Draw a straight line from X to Z, and from W to Y. Now square WXYZ is divided into 4 equal triangles. The area of each triangle is just ¼ of the area of the square.
Notice that areas B and C can be combined to form a triangle. This triangle is identical to each of the 4 triangles , and has the same area.
Final answers for a) and b) are 3.43cm² and 19.43cm² respectively , correct to two decimal places.
Subtract the area of the inner circle from the area of square WXYZ to get the area of the 4 corners.
Each is equal to A. So divide by 4 to get your answer.
b)
Draw a straight line from X to Z, and from W to Y. Now square WXYZ is divided into 4 equal triangles. The area of each triangle is just ¼ of the area of the square.
Notice that areas B and C can be combined to form a triangle. This triangle is identical to each of the 4 triangles , and has the same area.
Final answers for a) and b) are 3.43cm² and 19.43cm² respectively , correct to two decimal places.
Thank you for the tips but I get 19.43 for (b) as 1/4 of 64 is 16 (B+C) add 3.43 (A), total 19.43cm2. Did I do wrongly?
Your working is correct. Typo error on my side. Have edited.
Thank you so much. Your explanation is v clear. Thumbs up!!
Welcome! Glad it helped
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Date Posted:
4 years ago
Thank you. How about part (b)? What would be the solution?
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