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secondary 3 | A Maths
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I need help with question 12. I just started this topic at school and I am confused on what laws to apply. Pls help me, thank you :)
Date Posted: 4 years ago
Views: 222
For this question, you need to make use of these properties :
log(a) + log(b) = log(a x b) = log(ab) ①
log(a) - log(b) = log(a ÷ b) = log (a/b) ②
a log(b) = log(b^a) ③
So lg(3x) + lg(4y) - lg(x²/y)
= lg(3x × 4y) - lg(x²/y)
(Property ①)
= lg(12xy) - lg(x²/y)
= lg(12xy ÷ x²/y)
(Property ②)
= lg(12xy × y/x²)
= lg(12y²/x)
Try part b on your own. You will need property ③. The final answer is ln(y^6/x²) or 2ln(y³/x).
log(a) + log(b) = log(a x b) = log(ab) ①
log(a) - log(b) = log(a ÷ b) = log (a/b) ②
a log(b) = log(b^a) ③
So lg(3x) + lg(4y) - lg(x²/y)
= lg(3x × 4y) - lg(x²/y)
(Property ①)
= lg(12xy) - lg(x²/y)
= lg(12xy ÷ x²/y)
(Property ②)
= lg(12xy × y/x²)
= lg(12y²/x)
Try part b on your own. You will need property ③. The final answer is ln(y^6/x²) or 2ln(y³/x).
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Hi Carolyn! Here are my explanations for this question.
Date Posted:
4 years ago
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