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Primary 4 | Maths
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Julie
Julie

Primary 4 chevron_right Maths chevron_right Singapore

Need help for the solution of this question.

Date Posted: 3 months ago
Views: 54
Eric Nicholas K
Eric Nicholas K
3 months ago
The extra 3 rulers would have cost $6, since that is the difference in outcome between “$2 extra” and “short of $4”.

3 rulers —> $6
1 ruler —> $6 divided by 3 = $2
38 rulers —> $2 x 38 = $76

Since he still has $2 spare, amount of money he has is $76 + $2 = $78.

Alternatively,

41 rulers —> 2 x $41 = $82

He does not have enough money as he is short of $4.

Amount of money he has is $82 - $4 = $78.
snell
Snell
3 months ago
method 1

cost of 1 ruler: u

amt of money at first: 41u - 4

amt of money at first: 38u + 2

41u - 4= 38u + 2
u = $2

amt of money at first = 41x2 - 4 = $78


method 2

cost of 1 ruler
= (4+2)/(41-38) [ sum ÷ difference ]
= 6/3
= $2

amt of money at first = 38x2 + 2 = $78


...

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Claudine Lim
Claudine Lim's answer
16 answers (Tutor Details)
1st
Tip: use simultaneous equations to solve for unknowns

One equation for each statement
Eric Nicholas K
Eric Nicholas K
3 months ago
Primary 4 students have not learnt simultaneous equations yet. These are for secondary 2 students and above.
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Xanthia Lye
Xanthia Lye's answer
22 answers (Tutor Details)
done using algebra