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primary 6 | Maths
| Data Analysis
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Please help
Date Posted: 5 years ago
Views: 346
given:
A is 2 1/3 times of B
=> A = 2 1/3 x B
=> A = 7/3 x B
multiply both sides by 3/7,
=> 3/7 x A = 7/3 x B x 3/7
=> 3/7 x A = B
=> B = 3/7 x A
so B is 3/7 times of A.
...
A is 2 1/3 times of B
=> A = 2 1/3 x B
=> A = 7/3 x B
multiply both sides by 3/7,
=> 3/7 x A = 7/3 x B x 3/7
=> 3/7 x A = B
=> B = 3/7 x A
so B is 3/7 times of A.
...
Why do we need to multiply by 3/7? Where do we retrieve that?
good qn!
do u see
=> A = 7/3 x B ???
the next step is convert the right side of 7/3 x B into B (bcos we want B on one side)
how to do that?
on the right side,
multiply 7/3 x B by 3/7
=> 7/3 x B x 3/7
=> 7/3 x 3/7 x B
=> 1/1 x B
=> B
in addition, in equation, when we multiply one side by a number, we hv to multiply the other side by the same number so as not to mess up the equation. (just to make it correct mathematically)
hence, we multiply both sides by 3/7.
...
do u see
=> A = 7/3 x B ???
the next step is convert the right side of 7/3 x B into B (bcos we want B on one side)
how to do that?
on the right side,
multiply 7/3 x B by 3/7
=> 7/3 x B x 3/7
=> 7/3 x 3/7 x B
=> 1/1 x B
=> B
in addition, in equation, when we multiply one side by a number, we hv to multiply the other side by the same number so as not to mess up the equation. (just to make it correct mathematically)
hence, we multiply both sides by 3/7.
...
See 1 Answer
done
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For this kind of question, form a fraction that expresses the relationship between the 2 as a ratio. Manipulate the fraction (eg. “flip”, and/or “bring over” terms) to obtain desired form
Date Posted:
5 years ago
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