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secondary 4 | E Maths
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How to show if BXC similar to ABC
Date Posted: 5 years ago
Views: 214
∠CXY = ∠AXB (vertically opposite angles)
∠ABX = ∠CYX (alternate angles, AB // DC)
∠BAX = ∠YCX (alternate angles, AB // DC)
(AB // DC since ABCD is a rectangle and AB and DC are opposite sides of it)
Since all 3 pairs of corresponding angles in both triangles are equal ,they are similar (Angle Angle similarity or AAA)
(You actually only need two pairs of corresponding angles. Because it can be shown from there that the third pair of corresponding angles are equal)
∠ABX = ∠CYX (alternate angles, AB // DC)
∠BAX = ∠YCX (alternate angles, AB // DC)
(AB // DC since ABCD is a rectangle and AB and DC are opposite sides of it)
Since all 3 pairs of corresponding angles in both triangles are equal ,they are similar (Angle Angle similarity or AAA)
(You actually only need two pairs of corresponding angles. Because it can be shown from there that the third pair of corresponding angles are equal)
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