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secondary 4 | E Maths
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Darren
Darren

secondary 4 chevron_right E Maths chevron_right Singapore

Please show step by step of how u get for part C) thanks u so much

Date Posted: 3 months ago
Views: 24
J
J
3 months ago
u1 = 2^0 + 1 = 2^(1-1) + (2 x 1 - 1)
u2 = 2¹ + 3 = 2^(2-1) + (2 x 2 - 1)
u3 = 2² + 5 = 2^(3-1) + (2 x 3 - 1)
u4 = 2³ + 7 = 2^(4-1) + (2 x 4 - 1)

See the pattern? It's always 2^(term number - 1) + (2 x term number - 1)

so for c) we're finding the nth term. It's just

un = 2^(n-1) + 2n - 1

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Alvin
Alvin's answer
6 answers (A Helpful Person)
1st
here
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Poh Jing Seng
Poh Jing Seng's answer
4 answers (Tutor Details)
You just got to look for the trends, I really don't know how to explain that but all i can say is focus on the numbers in relation with "n".