Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 2 | Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Date Posted: 4 years ago
Views: 299
numerator:
e⁴f² - e³f³ = e³f²(e - f)
denominator:
e²f⁴ - e³f³ = e²f³(f - e) = -e²f³(e - f)
hence,
(e⁴f² - e³f³)/(e²f⁴ - e³f³)
= [e³f²(e - f)]/[-e²f³(e - f)]
= -e/f
e⁴f² - e³f³ = e³f²(e - f)
denominator:
e²f⁴ - e³f³ = e²f³(f - e) = -e²f³(e - f)
hence,
(e⁴f² - e³f³)/(e²f⁴ - e³f³)
= [e³f²(e - f)]/[-e²f³(e - f)]
= -e/f
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope it helps
Date Posted:
4 years ago
360 Tutoring Program