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Question
primary 6 | Maths
| Geometry
One Answer Below
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Date Posted: 4 years ago
Views: 362
angle ECF = 180 - 40 - 40 = 100deg
angle DCB = angle ECF = 100deg
(a)
since AB // DC ,
angle ABC = 180 - angle DCB = 80deg
(b)
angle CFE = 40deg
angle BEF = 180 - 40 - 40 =100deg
angle BEC = angle BEF - 40 = 60deg
angle DCB = angle ECF = 100deg
(a)
since AB // DC ,
angle ABC = 180 - angle DCB = 80deg
(b)
angle CFE = 40deg
angle BEF = 180 - 40 - 40 =100deg
angle BEC = angle BEF - 40 = 60deg
See 1 Answer
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hopefully this helps
Date Posted:
4 years ago
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