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Question
primary 6 | Maths
| Geometry
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Date Posted: 4 years ago
Views: 284
since MNQR is rhombus,
triangle MNR is isos.
angle MRN = (180-104)/2 = 38deg
angle NRP
= angle MRQ - angle MRN -angle PRQ
= 22deg
(b)
angle RUP = 360-320 = 40deg
angle RUP + angle URT + angle MRN + angle NRP + angle RPU = 180deg
40deg + angle URT + 38deg + 22deg + angle RPU = 180deg
angle URT + angle RPU
= 180-40-38-22 = 80deg
triangle MNR is isos.
angle MRN = (180-104)/2 = 38deg
angle NRP
= angle MRQ - angle MRN -angle PRQ
= 22deg
(b)
angle RUP = 360-320 = 40deg
angle RUP + angle URT + angle MRN + angle NRP + angle RPU = 180deg
40deg + angle URT + 38deg + 22deg + angle RPU = 180deg
angle URT + angle RPU
= 180-40-38-22 = 80deg
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Official answer by Snell in the comments below
Date Posted:
4 years ago
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