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primary 6 | Maths | Percentage
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Jovel
Jovel

primary 6 chevron_right Maths chevron_right Percentage chevron_right Singapore

Sorry is not percent but is circle I need help in this question

Date Posted: 4 years ago
Views: 670
J
J
4 years ago
Draw a line from A and from B to the middle of line PQ. You'll see 2 triangles.

half of each shaded area
= Area of quarter circle - area of 1 triangle

You'll just need to multiply the result by 4 to get the required answer.
Jovel
Jovel
4 years ago
Sorry I still don’t understand clearly
J
J
4 years ago
refer to the picture I posted below

See 3 Answers

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C Meen
C Meen's answer
81 answers (A Helpful Person)
1st
Part 1
Jovel
Jovel
4 years ago
Thank you
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C Meen
C Meen's answer
81 answers (A Helpful Person)
Part 2. Hope you understand
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J
J's answer
1022 answers (A Helpful Person)
See the two triangles?

Subtract the area of one triangle from area of one quarter circle.

Then you'll notice there are a total of 4 of the same shaded portions. So just need to multiply by 4 to get the total area of the shaded parts
J
J
4 years ago
Since radius = 7cm,

Area of one quarter circle
= ¼ x 22/7 x 7cm x 7cm
= 38½cm²

Area of one triangle
= ½ x 7cm x 7cm
= 24½cm²

One smaller shaded portion
= 38½cm² - 24½cm²
= 14cm²

There are 4 of the same kind of smaller shaded portions in total.

So total area of shaded parts
= 14cm² x 4 = 56cm²




Alternatively,

The two triangles make up 1 bigger triangle.

Area of semicircle = ½ x 22/7 x 7cm x 7cm
= 77cm²

Area of bigger triangle
= ½ x 14cm x 7cm
= 49cm²

77cm² - 49cm² = 28cm²

After subtracting you'll get 2 of the shaded portions. There are 4 of them so you'll multiply by 2 .

28cm² x 2 = 56cm²