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Secondary 1 | Maths
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Celine
Anonymous

Secondary 1 chevron_right Maths chevron_right Singapore

Pls help me with this question, thanks!

Date Posted: 5 years ago
Views: 412
J
J
5 years ago
Find the HCF OF 630 and 396.

630
= 2 x 315
= 2 x 3 x 105
= 2 x 3 x 3 x 35
= 2 x 3 x 3 x 5 x 7
= 2 x 3² x 5 x 7

396
= 2 x 198
= 2 x 2 x 99
= 2 x 2 x 3 x 33
= 2 x 2 x 3 x 3 x 11
= 2² x 3² x 11

As you can see from above,

2, 3² are common. So HCF = 2 x 3² = 18

So the largest possible length of a side of the square is 18cm.


ii)

396 ÷ 18 = 22
630 ÷ 18 = 35

So least number of squares
= 35 x 22
= 770


OR

Least number of squares
= Area of board ÷ area of 1 square

= (630 x 396) ÷ (18 x 18)
= 770



Largest possible length of a square
= 18cm

18 = 2 x 3 x 3

So the second largest possible length must be (3 x 3) since it's the next biggest factor of 18

(3 x 3)cm = 9cm

you can solve b ii) on your own

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Jermine
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18cm