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secondary 4 | A Maths
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Please help for (b)(ii), is this question common?
Date Posted: 4 years ago
Views: 287
You will have to follow the general formula for binomial expansion, with one extra note.
(n choose r) = n! / (n-r)!
From there you should able to get n in terms of a number instead of an expression.
For part ii, you will have to multiply the terms which will multiply to give you a constant (no x). Equate that to zero and you should be able to find n.
Unfortunately I am outside and unable to give a pictorial solution. If there are no other solutions tonight I will try and write one for you
(n choose r) = n! / (n-r)!
From there you should able to get n in terms of a number instead of an expression.
For part ii, you will have to multiply the terms which will multiply to give you a constant (no x). Equate that to zero and you should be able to find n.
Unfortunately I am outside and unable to give a pictorial solution. If there are no other solutions tonight I will try and write one for you
Ok thank you!
Sent the first part. If you do not mind tediousness, you can also do this question the “fool’s way” and expand everything until you find the term in x^-2. The same answer should be obtained.
Thank you very much
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First part, let me know if you need more explanations
Date Posted:
4 years ago
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Second part
Date Posted:
4 years ago
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