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secondary 4 | A Maths
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Please help me with question 5.
AEF is also 90 since it is given
It has to be the case that AB is parallel to EF.
(ii) Angle 1 = Angle 2 because BC = DC
But Angle 1 = Angle 2 because of vertically opposite angles, while Angle 3 = Angle 4 by alternate angles
So all four angles are equal.
Since Angle 2 = Angle 4, FD = FE.
(iii) We can just call FD and FE names such as radii, since they are equal in length and radii are known for being equal in length all the time.
F can be the centre of ONE possible circle passing through D and E.