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secondary 4 | A Maths
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Germaine
Germaine

secondary 4 chevron_right A Maths chevron_right Singapore

Please help me with question 5.

Date Posted: 4 years ago
Views: 250
Eric Nicholas K
Eric Nicholas K
4 years ago
5 (i) AB is diameter and EA is tangent at A so EAB is 90

AEF is also 90 since it is given

It has to be the case that AB is parallel to EF.

(ii) Angle 1 = Angle 2 because BC = DC
But Angle 1 = Angle 2 because of vertically opposite angles, while Angle 3 = Angle 4 by alternate angles

So all four angles are equal.

Since Angle 2 = Angle 4, FD = FE.

(iii) We can just call FD and FE names such as radii, since they are equal in length and radii are known for being equal in length all the time.

F can be the centre of ONE possible circle passing through D and E.