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secondary 4 | A Maths
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Kathy
Kathy

secondary 4 chevron_right A Maths chevron_right Singapore

Thank you

Date Posted: 4 years ago
Views: 722
Pathoxye
Pathoxye
4 years ago
Differentiate the equation and let dy/dx = 0 to find the stationary points. Determine whether it's min or max point then from there you can sketch the curve

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
Done. I have used the second derivative test instead of the first derivative test for the nature of the stationary points (max, min or inflection) as the expression for dy/dx is quite simple.
Kathy
Kathy
4 years ago
What u mean by first or second
Eric Nicholas K
Eric Nicholas K
4 years ago
There are two different ways of checking the nature of the stationary points. One method is the first derivative test, which looks at the values of dy/dx around a stationary point. The other method is the second derivative test, which tells us directly the nature given the signage of d2y/dx2.
Eric Nicholas K
Eric Nicholas K
4 years ago
Let me know if you need me to write down both methods.
Kathy
Kathy
4 years ago
Sorry I still don’t get it on this
Eric Nicholas K
Eric Nicholas K
4 years ago
Ok wait, I will need some time to write down the explanations.
Kathy
Kathy
4 years ago
Ok.
Did u saw my qns on 3b that I comment it
Eric Nicholas K
Eric Nicholas K
4 years ago
Wait let me see, I will after that write down the workings for this question
Kathy
Kathy
4 years ago
Ok
Eric Nicholas K
Eric Nicholas K
4 years ago
I could not find it. At a much later time I switch on my phone and see if I can find it.
Kathy
Kathy
4 years ago
Ok thank you
Eric Nicholas K
Eric Nicholas K
4 years ago
You can read up on my notes first
Kathy
Kathy
4 years ago
can
Kathy
Kathy
4 years ago
Can u find the qns ?
Eric Nicholas K
Eric Nicholas K
4 years ago
Done
Eric Nicholas K
Eric Nicholas K
4 years ago
You can post the next one once ready
Kathy
Kathy
4 years ago
Tomorrow I will post, too many right now
Thank you
Eric Nicholas K
Eric Nicholas K
4 years ago
I will be available tmr from 11:30 pm onwards; I can do bit by bit while I am outside from 7 pm onwards.
Eric Nicholas K
Eric Nicholas K
4 years ago
Forgot to add that I will most likely not be available until probably 12 am because my phone is still down
Kathy
Kathy
4 years ago
I posted a qns
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Eric Nicholas K
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5997 answers (Tutor Details)
First page of my own notes
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Eric Nicholas K
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Eric Nicholas K
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Fifth page, first part
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Eric Nicholas K
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Fifth page, second part
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Eric Nicholas K
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Last page
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Eric Nicholas K
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5997 answers (Tutor Details)
Done