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secondary 3 | E Maths
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Sorry but i really need help thank you so much !
Date Posted: 4 years ago
Views: 535
SAS similarity.
angle DAC = angle EAB (common angle)
AE/AD = 6/(3.6 + 6) = 6/9.6 = 5/8 or 0.625
AB/AC = 7/(7 + 4.2) = 7/11.2 = 5/8 or 0.625
So, AB/AC = AE/AD
Since ratios of two corresponding sides are equal and the included angle is the same, by SAS the two triangles are similar.
Use the ratio to solve part b.
angle DAC = angle EAB (common angle)
AE/AD = 6/(3.6 + 6) = 6/9.6 = 5/8 or 0.625
AB/AC = 7/(7 + 4.2) = 7/11.2 = 5/8 or 0.625
So, AB/AC = AE/AD
Since ratios of two corresponding sides are equal and the included angle is the same, by SAS the two triangles are similar.
Use the ratio to solve part b.
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Important to take note on what values tue question provides. In this case using the SAS (Side-Angle-Side) method is the quickest and least complicated.
Date Posted:
4 years ago
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