Can you check for me why the normal part my book answer is different from you

Kathy, I made a mistake in the copying, carrying forward the error. I miswrote the x = 1, y = -3 as (1, 3). I will redo this one later. Just finished teaching my student techniques on trigo identity solving.

Ok. Thanks

That means for the tangent and normal, 1, -3 should be used instead of 1, 3.

Are u around?

I will help you once ready

Kathy, my phone ran into the same trouble again. I will upload my answers by scanning shortly and then answer questions from online.

I thought u will change all, haha.
I try myself

Which one would you like me to change? I will help you later once I am ready.

The techniques to form equations of tangent and normal to a curve at a specific point are as follows.

1. Obtain the coordinates required for the tangent. If the question says “find the equation...at x = 2”, we need to find the value of y based on the equation of the curve for the coordinates.

2. Obtain dy/dx of the curve for any general point and then sub in the x-value of the coordinate to find the value of dy/dx at that x-value. This is the gradient of the tangent. For the normal, the new value is -1 divided by this number.

3. Now that you have the coordinates and the gradient, you can then form the equation using your y = mx + c.

Qns 2 and qns 3

Ok will redo them once ready, I am about to finish a question from another person and then doing other things first. Writing up Q2 and Q3 at 3 pm.

Ok. Thanks

Thank you. I post a new chapter

Ok wait