## Ask Singapore Homework?

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### See 5 Answers

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Q1, same idea as the previous question

Date Posted:
1 month ago

Can you check for me why the normal part my book answer is different from you

Ok. Thanks

That means for the tangent and normal, 1, -3 should be used instead of 1, 3.

Are u around?

I will help you once ready

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This method of finding equations of tangents extends to curves which are not polynomials, such as graphs of ln x and so on.

Date Posted:
1 month ago

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Here

Date Posted:
1 month ago

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Q1, corrected version

Date Posted:
1 month ago

I thought u will change all, haha.

I try myself

I try myself

Which one would you like me to change? I will help you later once I am ready.

1. Obtain the coordinates required for the tangent. If the question says “find the equation...at x = 2”, we need to find the value of y based on the equation of the curve for the coordinates.

2. Obtain dy/dx of the curve for any general point and then sub in the x-value of the coordinate to find the value of dy/dx at that x-value. This is the gradient of the tangent. For the normal, the new value is -1 divided by this number.

3. Now that you have the coordinates and the gradient, you can then form the equation using your y = mx + c.

Qns 2 and qns 3

Ok. Thanks

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Q2, Q3, redone

Date Posted:
1 month ago

Thank you. I post a new chapter

Ok wait