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secondary 4 | A Maths
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Sonia
Sonia

secondary 4 chevron_right A Maths chevron_right Singapore

Hi... Please help me with this :(

Date Posted: 1 month ago
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Jiayang
Jiayang's answer
1883 answers (Tutor Details)
1st
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Eric Nicholas K
Eric Nicholas K's answer
2950 answers (Tutor Details)
Hi Sonia! Here is how we obtain dy/dx for that expression. I have included two different approaches to obtaining dy/dx. Next up is the remaining part the stationary points and their nature.
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Eric Nicholas K
Eric Nicholas K's answer
2950 answers (Tutor Details)
At the turning points, remember: the tangent to the curve at that point will always be horizontal, with a gradient of 0, so dy/dx = 0 at these points.

You have converted a differentiation question into a trigo question which you will need the trigo knowledge which you have learnt.