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Question
primary 5 | Maths
| Fractions
2 Answers Below
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Pls help. Tq
Date Posted: 4 years ago
Views: 272
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Hope this help
Date Posted:
4 years ago
May i know why need times 3?
We need to eliminate either cake or pie, in this case, cake have more u. i.e 6u, so we choose to eliminate the pie. 3u, therefore we able to find cake 1u.
Total
Cake =6u
Pie=3u
Given 1cake and 1pie=80
3 cake + 3 pie = 240 (all time 3)
Total cake and pie = 300
3 cake + 3 cake +3 pie = 300
3 cake + ( 240) = 300 —-> 240 = 3cake +3pie
....
.... 1cake=20
Total
Cake =6u
Pie=3u
Given 1cake and 1pie=80
3 cake + 3 pie = 240 (all time 3)
Total cake and pie = 300
3 cake + 3 cake +3 pie = 300
3 cake + ( 240) = 300 —-> 240 = 3cake +3pie
....
.... 1cake=20
Got it. Thank u so much.
done
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Ans: 120
Date Posted:
4 years ago
Thank u
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