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secondary 4 | E Maths
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shinoa
Shinoa

secondary 4 chevron_right E Maths chevron_right Singapore

Pls help me thanks in advance

Date Posted: 4 years ago
Views: 221
J
J
4 years ago
x² - 11x + 12

Recall that (a - b)² = a² - 2ab + b²

So if you compare the expressions, you'll realise that 2ab = 11x and we can equate x to a.


So 2ab = 11a and thus b = 11/2

So we can write :

x² - 11x + 12

= x² - 11x + (11/2)² +12 - (11/2)²

= (x - 11/2)² + 12 - 121/4

= (x - 11/2)² - 73/4

= (x - 5½)² - 18¼

so your p = 5½ and q = 18¼


b)

(x - 5½)² - 18¼ = 0


(x - 5½)² = 18¼

x - 5½ = ± √18¼


x = 5½ ± √18¼

Answer is same as what you've gotten

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
The trick here is to introduce a term equal to the square of half the coefficient of x.

Here the coefficient of x is -11, so we need to introduce the square of half of this, or the square of (-11/2), or (-11/2)^2.

Of course, we “borrowed” this term to complete the square, so we must “return” it afterwards.

The first three terms which I wrote combine to form a two-term combination inside the bracket, since the three terms a2 + 2ab + b2 combine to form (a + b)^2.

The alternative method is to compare your given expression with the formula a2 + 2ab + b2 and find out what a and b are.

As a side note, your quadratic formula for solving quadratic equations is actually derived from the technique of completing the square.