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secondary 3 | E Maths
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i need help for (f) SOS!!
Date Posted: 4 years ago
Views: 236
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Hope this helps
Date Posted:
4 years ago
i suppose shoelace method isnt allowed in emath ??
This is a good question. There are many ways to solve a question. So if I am the teacher I don't think this method should be penalized, but if you are using methods other than shoelace method, you can consider this.
Shoelace method just so happen to be the first method I thought of in solving this
Part c) use the x coordinate difference between A and C to get the base, then use the y coordinate difference between B and C to get the height. Then use Area = 1/2(base)(height)
Part f)
Knowing that area of trapezium = (1/2)(sum of parallel sides) (height)
You have the area and height (which is AC). Sum of parallel sides can be distance BC and AD which will leave you with x coordinate as the unknown.
Alternatively you can try to see if gradient BC = gradient AD
Shoelace method just so happen to be the first method I thought of in solving this
Part c) use the x coordinate difference between A and C to get the base, then use the y coordinate difference between B and C to get the height. Then use Area = 1/2(base)(height)
Part f)
Knowing that area of trapezium = (1/2)(sum of parallel sides) (height)
You have the area and height (which is AC). Sum of parallel sides can be distance BC and AD which will leave you with x coordinate as the unknown.
Alternatively you can try to see if gradient BC = gradient AD
Part c and e has some changes due to a miss out in numbers in part c. See new solution for answer
done
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Second portion to show that other ways are possible.
Note that I have forgotten to include the 1/2 in part c in the previous solution so here is the correct answer. Part e is also affected as a result.
For part f, I mentioned that the gradient may be used. But what I did not realized is that D is actually in line with B which gives a gradient of zero. Thus that method is not possible in this case. I have included the other method to solve part f as well.
Hope it helps
Note that I have forgotten to include the 1/2 in part c in the previous solution so here is the correct answer. Part e is also affected as a result.
For part f, I mentioned that the gradient may be used. But what I did not realized is that D is actually in line with B which gives a gradient of zero. Thus that method is not possible in this case. I have included the other method to solve part f as well.
Hope it helps
Date Posted:
4 years ago
Thank you!!!
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