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Question
primary 6 | Maths
| Geometry
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Pls help
Date Posted: 4 years ago
Views: 452
△ABQ = △BCQ = ½ of square ABCQ
BQ // AP
→ △ABQ = △PBQ (base same ; height same)
→ △ACQ = △PBQ + △BCQ = square ABCQ
= ½ of rectangle PQRS
→ shaded area = emicirlce + △ABQ
→ ½ ×π×5cm×5cm + 25cm² = 64.25cm² (Ans)
BQ // AP
→ △ABQ = △PBQ (base same ; height same)
→ △ACQ = △PBQ + △BCQ = square ABCQ
= ½ of rectangle PQRS
→ shaded area = emicirlce + △ABQ
→ ½ ×π×5cm×5cm + 25cm² = 64.25cm² (Ans)
See 1 Answer
done
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clear
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(a) 25cm²
(b) 64.25cm²
(b) 64.25cm²
Date Posted:
4 years ago
Thanks for the clear explanation
Thanks for the working
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