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secondary 2 | Maths
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pls help me solve part 2 of this sec 2 math qn thanku! :)
Date Posted: 4 years ago
Views: 212
G“Inversely proportional to 1/(x + 4)” is the same as “directly proportional to (x + 4)”. Be careful with the wording here.
From there, you will create the equation y = k (x + 4) for some unknown k to be found. We then use the condition x = 1, y = 10 to obtain k = 2. From there, we use the result y = 2 (x + 4) to solve for a and b.
When x = 2, y = a
a = 2 (2 + 4) = 12
When x = b, y = 5
5 = 2 (b + 4)
2.5 = b + 4
b = -1.5
From there, you will create the equation y = k (x + 4) for some unknown k to be found. We then use the condition x = 1, y = 10 to obtain k = 2. From there, we use the result y = 2 (x + 4) to solve for a and b.
When x = 2, y = a
a = 2 (2 + 4) = 12
When x = b, y = 5
5 = 2 (b + 4)
2.5 = b + 4
b = -1.5
See 1 Answer
done
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Hope this help
Date Posted:
4 years ago
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