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4y = 37y - 90 - 3y2
3y2 - 33y + 90 = 0
y2 - 11y + 30 = 0
(Not y2 - 11y + 10 = 0)
...
(Likely a miscomputation there)
3y2 - 33y + 90 = 0
y2 - 11y + 30 = 0
(Not y2 - 11y + 10 = 0)
...
(Likely a miscomputation there)
done
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The trigo one
Date Posted:
4 years ago
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The simul one. I have a different answer from the other tutor, but I have resubstituted the two possible pairs of answers which I have obtained and found that both pairs are valid.
Date Posted:
4 years ago
Posted a qns