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secondary 4 | E Maths
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Date Posted: 4 years ago
Views: 329
The bottom number is 2^(n - 1).
The top number is the bottom number plus 3.
So if a term is m/n, m must be n + 3. So the next term’s denominator is 2n while the numerator is 2n + 3. The next term must be (2n + 3) / 2n.
200 is not a power of 2, so this will not appear in the sequence.
The top number is the bottom number plus 3.
So if a term is m/n, m must be n + 3. So the next term’s denominator is 2n while the numerator is 2n + 3. The next term must be (2n + 3) / 2n.
200 is not a power of 2, so this will not appear in the sequence.
Sorry misread the question.
The previous term’s denominator is 0.5n, and the numerator is 0.5n + 3.
So the fraction is (0.5n + 3) / 0.5n = (n + 6) / n.
The previous term’s denominator is 0.5n, and the numerator is 0.5n + 3.
So the fraction is (0.5n + 3) / 0.5n = (n + 6) / n.
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Took a while to get this out. But hope this still helps
Date Posted:
4 years ago
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