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secondary 3 | E Maths
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Help pleasee
Date Posted: 4 years ago
Views: 217
This question is not easy. It makes use of this concept:
For a system in equilibrium, the sum of anti clockwise moments is the same as the sum of clockwise moments about the same point.
We can define this point to be anywhere on the system, not just the pivots.
To find the force on trestle A, we set the ‘pivot’ to be at trestle B, because the moment about trestle B would be zero (the pivot is at B itself so there is no distance from the said pivot).
Similarly, to find the force on trestle B, we set the ‘pivot’ to be at trestle A.
For a system in equilibrium, the sum of anti clockwise moments is the same as the sum of clockwise moments about the same point.
We can define this point to be anywhere on the system, not just the pivots.
To find the force on trestle A, we set the ‘pivot’ to be at trestle B, because the moment about trestle B would be zero (the pivot is at B itself so there is no distance from the said pivot).
Similarly, to find the force on trestle B, we set the ‘pivot’ to be at trestle A.
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Note that its advised to express answers to 2 significant figures for this question. The rationale for Physics is that you cannot calculate more accurately than what is measured - the smallest significant figure used in the question was 2 sig. Fig, so answers should match. For O-levels, they still allow you to get away with 3 s.f.
Date Posted:
4 years ago
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