Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.



Question

junior college 1 | H2 Maths
One Answer Below

Anyone can contribute an answer, even non-tutors.

Answer This Question
Kenneth Cheng
Kenneth Cheng

junior college 1 chevron_right H2 Maths chevron_right Singapore

Solve the following question

Date Posted: 4 years ago
Views: 433
J
J
4 years ago
dy/dx - 6y/x = 2x + 10/x

Multiply both sides by 1/x^6,

1/x^6 dy/dx - 6y/x^7 = 2/x^5 + 10/x^7

d/dx (y/x^6) = 2/x^5 + 10/x^7

∫ d/dx (y/x^6) dx = ∫ (2/x^5 + 10/x^7) dx

y/x^6 = 2/((-4)x⁴) + 10/((-6)x^6) + C, C is a constant

y/x^6 = -1/(2x⁴) - 5/(3x^6) + C

y = -½x² - 5/3 + Cx^6

See 1 Answer

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
Kenneth Chee
Kenneth Chee's answer
179 answers (A Helpful Person)
1st