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secondary 4 | E Maths
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Pauline
Pauline

secondary 4 chevron_right E Maths chevron_right Singapore

Send help pls! Thanks

Date Posted: 4 years ago
Views: 263

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
Part (a)

I have long forgotten this topic already (I last touched this topic almost 10 years ago) so my concepts may be rusty but I have tried my best to come up with the idea.

By the way, this topic is only seen beyond the O Levels and should not be seen in Sec 4.
Eric Nicholas K
Eric Nicholas K
4 years ago
Part b

This one is straightforward. It doesn’t matter what the gender of the people is - we can just select the people randomly since there are no restrictions on the gender composition of each group. So we have 8 people to select from (obviously all are distinguishable).

We choose 3 out of 8 people to go into the first group. The remaining people will have no choice but to be in the other group. Alternatively, we can also choose 5 out of 8 people to go into the first group and the remaining three will automatically be in the other group. Either way, there are a total of 8C3 (or 8C5 which also gives the same answer) which equals 56 ways.

Sorry that I sent in my answer for part b through this text as I was unable to send in my answers for part b successfully even though my internet connection is working.