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Question
primary 5 | Maths
| Area & Volume
2 Answers Below
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Can anyone please help? Thank you.
Date Posted: 5 years ago
Views: 347
AD = 26cm - 22cm = 4cm
Unshaded triangle and triangle ABC are similar (all 3 corresponding angles are the same)
base of ABC = 24cm
base of unshaded triangle = AD = 4cm
Ratio of base of ABC to unshaded triangle's base = 24 : 4 = 6 : 1
For similar triangles, ratio of their corresponding sides are the same.
So height of ABC : height of unshaded triangle = 6 : 1
Since height of ABC = 10cm, height of unshaded triangle = 10cm ÷ 6 = 1⅔cm
Area of unshaded triangle = ½ x 1⅔cm x 4cm = 3⅓cm²
Area of ABC = ½ x 10cm x 24cm
= 120cm²
Shaded area = 120cm² - 3⅓cm² = 116⅔cm²
Unshaded triangle and triangle ABC are similar (all 3 corresponding angles are the same)
base of ABC = 24cm
base of unshaded triangle = AD = 4cm
Ratio of base of ABC to unshaded triangle's base = 24 : 4 = 6 : 1
For similar triangles, ratio of their corresponding sides are the same.
So height of ABC : height of unshaded triangle = 6 : 1
Since height of ABC = 10cm, height of unshaded triangle = 10cm ÷ 6 = 1⅔cm
Area of unshaded triangle = ½ x 1⅔cm x 4cm = 3⅓cm²
Area of ABC = ½ x 10cm x 24cm
= 120cm²
Shaded area = 120cm² - 3⅓cm² = 116⅔cm²
Thank you for your help!
You're welcome!
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Part1
Date Posted:
5 years ago
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Part 2
Date Posted:
5 years ago
Thank you so much for your answer.
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