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Question
secondary 4 | A Maths
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It will be great if you can solved qn 2(b). The answer in square root. I didn’t get the correct answer
= 4(x²)² - 7(x²)(y) - 2y²
= (4x² + y)(x² - 2y)
let x² = a and y = b²
Then try to factorise 4a - 7ab - 2b²
See 1 Answer
The x2 - 2y is not to be factorised into (x + sqrt (2y)) (x - sqrt (2y)).
Very rude of you to assert that he is not knowing the right answer and teaching the wrong concepts and assuming the 'correct' answer you have is absolutely correct.
You should be checking your answer scheme with your teacher (since you say your answer is in square root it is definitely a wrong answer as there is no square root in the correct answer) instead merely dismissing the detailed workings he has provided with that kind of reply
Do you know better than him? What more when two tutors give the same consistent answer?
Do not assume that your answer scheme is always correct. You are here to learn. We spend time and effort here to craft and provide answers free of charge, we are not here to be told things like ' please don't teach the wrong concept ' by people like you , who isn't qualified enough to do so.
Please don't act like you know better when you don't even know how to answer this question correctly.
That’s definitely the correct answer.
You DO NOT factorise (x² - 2y) into (x + √(2y))(x - √(2y)) at Sec 4 A Math, the topic you have stated