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primary 5 | Maths
| Fractions
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How to solve this problem
Date Posted: 4 years ago
Views: 1255
First scenario: Sasha gave Melissa 1/6 of her money.
Second scenario: Melissa then gave Sasha 3/7 of her money.
At the end: Both have equal amount of money.
($360 / 2) = $180
Each both have $180 at the end.
Melissa is left with 4/7 of her money which equals to $180. 1/7 = ($180 / 4) = $45. ($45 x 7) = $315. Hence, Melissa has $315 before she gave Sasha.
Sasha is left with ($360 - $315) = $45. Since she is left with 5/6, therefore 1/6 = ($45 / 5) = $9. Sasha has a total of ($9 x 6) = $54.
Since Sasha gave Melissa 1/6 of her money initially, Melissa only has ($315 - $9) = $306 at the beginning.
Answer:
Sasha: $54
Melissa: $306
Second scenario: Melissa then gave Sasha 3/7 of her money.
At the end: Both have equal amount of money.
($360 / 2) = $180
Each both have $180 at the end.
Melissa is left with 4/7 of her money which equals to $180. 1/7 = ($180 / 4) = $45. ($45 x 7) = $315. Hence, Melissa has $315 before she gave Sasha.
Sasha is left with ($360 - $315) = $45. Since she is left with 5/6, therefore 1/6 = ($45 / 5) = $9. Sasha has a total of ($9 x 6) = $54.
Since Sasha gave Melissa 1/6 of her money initially, Melissa only has ($315 - $9) = $306 at the beginning.
Answer:
Sasha: $54
Melissa: $306
See 1 Answer
done
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clear
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Do backward calculations
Hope this help
Hope this help
Date Posted:
4 years ago
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