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primary 6 | Maths
| Data Analysis

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And all the money is $24 (2400c).

The extra six more 50c coins translates to an extra $3.

Remove the six coins and you have an equal number of 50c and 20c coins which has a total value of $21.

Since the total value of all the ‘70c’ coins is $21 (2100c), there must have been 2100/70 = 30 of such ‘70c’ coins.

This means that the $21 consists of 30 of the 50c coins and 30 of the 20c coins. At the start there were 36 of the 50c coins and 30 of the 20c coins.