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secondary 3 | A Maths
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Date Posted: 4 years ago
Views: 242
(α+β)x+αβ
1/α + 1/β = (α + β)/αβ = -5/2
1/α x 1/β = 1/αβ = -3/2
(j)
(α + β)/αβ = -5/2
(α + β) x (-3/2) = -5/2
(α + β) = 5/3
(ii)
α² + β² = (α + β)² - 2αβ
= (-5/2)² - 2 x (-3/2)
= 25/4 + 3
= 37/4
α² x β² = (αβ)²
= (-3/2)²
= 9/4
eqn is:
x² - (37/4)x + (9/4) = 0
4x² - 37x + 9 = 0
1/α + 1/β = (α + β)/αβ = -5/2
1/α x 1/β = 1/αβ = -3/2
(j)
(α + β)/αβ = -5/2
(α + β) x (-3/2) = -5/2
(α + β) = 5/3
(ii)
α² + β² = (α + β)² - 2αβ
= (-5/2)² - 2 x (-3/2)
= 25/4 + 3
= 37/4
α² x β² = (αβ)²
= (-3/2)²
= 9/4
eqn is:
x² - (37/4)x + (9/4) = 0
4x² - 37x + 9 = 0
See 1 Answer
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Date Posted:
4 years ago
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