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primary 6 | Maths
| Fractions
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Elp.
Date Posted: 4 years ago
Views: 382
before,
A: 4u
B & C
after,
A: 3/4 x (3u) = 9u/4
B: B+u
C: C+ 3u/4
9u/4 = B+u
B = 5u/4
9u/4 = C + 3u/4
C = 6u/4
at first,
A has 4u
B has 5u/4
C has 6u/4
(a)
B has the least amt of money.
(b)
total = 4u + 5u/4 + 6u/4 = 6u + 3u/4
= 6.75u
A's money as a fraction of total
= 4/6.75 = 16/27
(c)
A = C + 330
4u = 6u/4 + 330
u = 132
total sum of money
= 6.75 x 132
= $891
A: 4u
B & C
after,
A: 3/4 x (3u) = 9u/4
B: B+u
C: C+ 3u/4
9u/4 = B+u
B = 5u/4
9u/4 = C + 3u/4
C = 6u/4
at first,
A has 4u
B has 5u/4
C has 6u/4
(a)
B has the least amt of money.
(b)
total = 4u + 5u/4 + 6u/4 = 6u + 3u/4
= 6.75u
A's money as a fraction of total
= 4/6.75 = 16/27
(c)
A = C + 330
4u = 6u/4 + 330
u = 132
total sum of money
= 6.75 x 132
= $891
See 1 Answer
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Hope this helps
Date Posted:
4 years ago
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