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secondary 3 | A Maths
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how do i continue pls help tyy
Date Posted: 4 years ago
Views: 258
Well done! You are at the right step already! Note that lg 3 divided by lg 2 is just an ordinary number, so the equation becomes
(x + 1)/x = k where k is your computed number
We make x the subject.
x + 1 = kx
kx - x = 1
x (k - 1) = 1
x = 1/(k - 1)
(x + 1)/x = k where k is your computed number
We make x the subject.
x + 1 = kx
kx - x = 1
x (k - 1) = 1
x = 1/(k - 1)
Also, we write (x + 1) lg 2 rather than x + 1 lg 2
This is because
x + 1 lg 2
is interpreted as x + lg 2 (multiplication comes before addition, whereas brackets come before outside multiplication)
This is because
x + 1 lg 2
is interpreted as x + lg 2 (multiplication comes before addition, whereas brackets come before outside multiplication)
See 2 Answers
done
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clear
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Two equally valid approaches to the question. Take your pick, one of the methods is probably easier for you.
Date Posted:
4 years ago
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