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secondary 3 | E Maths
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Pls help me with all the qns here and explain clearly I'm very Weak at this and tmr is exam pleas help
Date Posted: 4 years ago
Views: 220
Imagine ABCD is a parallelogram. Then the lines BC and AD are parallel to each other and equal in length
B to C is 15 units shift to the right. So A to D is also 15 units shift to the right. So D is (-2 + 15, 8) = (13, 8).
Similarly, if ADBC is a parallelogram, D to A is 15 units shift to the right, so D is (-2 - 15, 8) = (-17, 8).
There is one more case, ABDC is a parallelogram. A to C is 10 units to the right, 13 units down. So does B to D, so D is (-7 + 10, -5 - 13) = (3, -18).
B to C is 15 units shift to the right. So A to D is also 15 units shift to the right. So D is (-2 + 15, 8) = (13, 8).
Similarly, if ADBC is a parallelogram, D to A is 15 units shift to the right, so D is (-2 - 15, 8) = (-17, 8).
There is one more case, ABDC is a parallelogram. A to C is 10 units to the right, 13 units down. So does B to D, so D is (-7 + 10, -5 - 13) = (3, -18).
Use shoelace method for the aii.
Gradient of lines are given by the formula
(Y2 - Y1) / (X2 - X1)
Gradient of lines are given by the formula
(Y2 - Y1) / (X2 - X1)
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