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Question
secondary 4 | A Maths
5 Answers Below
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Date Posted: 5 years ago
Views: 377
Seen, later
sin 8A
= 2 sin 4A cos 4A
= 2 (2 sin 2A cos 2A) (1 - 2 cos2 2A)
And so on
= 2 sin 4A cos 4A
= 2 (2 sin 2A cos 2A) (1 - 2 cos2 2A)
And so on
Ok
See 5 Answers
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There should be a simpler form for this. Will look again later.
Date Posted:
5 years ago
I realised that there is a cos A at the end. If I have time later and can still remember, I will see if there is another way to evade the square roots, since I do not like the sight of square roots. Now doing the other two.
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For the upper part
Date Posted:
5 years ago
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For the question on simultaneous equations. Hope it helps.
Date Posted:
5 years ago
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Alternative
Date Posted:
5 years ago
Sadly the square root cannot be evaded. I tried other avenues also.
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Part b solution
Date Posted:
5 years ago
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