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primary 6 | Maths
| Fractions
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Date Posted: 5 years ago
Views: 265
4f + 7s = 2u
2f = 3s
4f = 6s
so
4f + 7s = 2u
6s + 7s = 2u
13s = 2u
money left = 5u
can buy 13/2 x 5 = 32.5 packets of sugar
BUT no 0.5 packet of sugar.
hence, the most no. of packets of sugar he can buy is 32.
2f = 3s
4f = 6s
so
4f + 7s = 2u
6s + 7s = 2u
13s = 2u
money left = 5u
can buy 13/2 x 5 = 32.5 packets of sugar
BUT no 0.5 packet of sugar.
hence, the most no. of packets of sugar he can buy is 32.
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