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junior college 2 | H2 Maths
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part iii
Date Posted: 4 years ago
Views: 277
P(A ∣ B') = P(A ∩ B') ÷ P(B')
0.88 = P(A ∩ B') ÷ P(B')
0.88 = P(A∩B') ÷ (P(A∩B') + P(A'∩B'))
0.88 = P(A∩B') ÷ ( P(A∩B') + 0.06 )
0.88 P(A∩B') + 0.88(0.06) = P(A∩B')
0.12 P(A∩B') = 0.0528
P(A∩B') = 0.44
P(A∩B) = P(A∪B) - P(A∩B') - P(A'∩B)
= 1 - P (A'∩B') - 0.44 - 0.24
= 1 - 0.06 - 0.44 - 0.24
= 0.26
OR
P(A∩B) = P(A) - P(A∩B')
= 0.7 - 0.44
= 0.26
0.88 = P(A ∩ B') ÷ P(B')
0.88 = P(A∩B') ÷ (P(A∩B') + P(A'∩B'))
0.88 = P(A∩B') ÷ ( P(A∩B') + 0.06 )
0.88 P(A∩B') + 0.88(0.06) = P(A∩B')
0.12 P(A∩B') = 0.0528
P(A∩B') = 0.44
P(A∩B) = P(A∪B) - P(A∩B') - P(A'∩B)
= 1 - P (A'∩B') - 0.44 - 0.24
= 1 - 0.06 - 0.44 - 0.24
= 0.26
OR
P(A∩B) = P(A) - P(A∩B')
= 0.7 - 0.44
= 0.26
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Date Posted:
4 years ago
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