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primary 6 | Maths
| Geometry
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Date Posted: 5 years ago
Views: 320
(a)
since QS is the diagonal of PQRS,
angle d is 45 deg.
(b)
angle QST = 45+90 = 135 deg
in triangle QST,
angle e = 180 - 23 - 135 = 22 deg
since QS is the diagonal of PQRS,
angle d is 45 deg.
(b)
angle QST = 45+90 = 135 deg
in triangle QST,
angle e = 180 - 23 - 135 = 22 deg
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Date Posted:
5 years ago
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