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Question
primary 6 | Maths
| Fractions
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Pls help. Tks
Date Posted: 4 years ago
Views: 720
in terms of area,
X = ⅓Y
Y = ⅔Z
unshaded Y = Y - X = Y - ⅓Y
= ⅔Y
unshaded Z = Z - X = Z - ⅓Y
= Z - (⅓ x ⅔Z) = Z - (2Z/9)
= 7Z/9
= 7/9 x Z
= 7/9 x 3Y/2
= 7/6 x Y
= 7Y/6
Fraction = unshaded Y ÷ unshaded Z
= ⅔Y ÷ 7Y/6
= 4/7
ans: (4)
X = ⅓Y
Y = ⅔Z
unshaded Y = Y - X = Y - ⅓Y
= ⅔Y
unshaded Z = Z - X = Z - ⅓Y
= Z - (⅓ x ⅔Z) = Z - (2Z/9)
= 7Z/9
= 7/9 x Z
= 7/9 x 3Y/2
= 7/6 x Y
= 7Y/6
Fraction = unshaded Y ÷ unshaded Z
= ⅔Y ÷ 7Y/6
= 4/7
ans: (4)
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Hope this helps too
Date Posted:
4 years ago
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