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secondary 4 | E Maths
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Eg: 144 = 1 x 1 x 144
Condition 1: Perimeter of top surface is 22 cm
Condition 2: All lengths are more than 2
Combination: 144 = 3 x 8 x 6 with top surface 3 cm and 8 cm (do perimeter is 3 + 8 + 3 + 8 = 22 cm)
So the height is 6 cm
It’s more of guesswork.
The fact that the three numbers are greater than 2 means you can try out 3 as the first number. Then you notice that 144/3 = 48 = 8 x 6. It so happens that 3 + 8 = 11 and doubling this will get you 22, the required perimeter. The other length, 6, must be the height.
144 = 3 x 6 x 8
144 = 3 x 4 x 12
144 = 3 x 3 x 16
144 = 4 x 4 x 9
144 = 4 x 6 x 6
(No more already)
Then from the list, you must find two numbers that add to 11 (half the perimeter of the rectangle)
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