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primary 6 | Maths
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Need help on P6-Maths-SA2-2016-Singapore-Chinese-Girls question 12
a)
Draw a line from F to D to form triangle CDF.
Triangle CDF and triangle CEF have the same height. Since CE is 3/4 of DC, the base of CEF is 3/4 of CDF. This tells you that the area of CEF is also 3/4 of CDF.
So area of triangle CDF = 24cm² ÷ 3 x 4
= 32cm²
b)
Area of ABF = twice of CEF
= 2 x 24cm²
= 48cm²
Notice that triangle ADF and triangle CDF have the same base length (which is the breadth of the triangle). Their combined height is the length of the rectangle ABCD
So, this means that their combined area = ½ x breadth x length of rectangle ABCD
= ½ area of ABCD
Combined area = 48cm² + 32cm²
= 90cm²
Area of ABCD = 2 x 90cm² = 180cm²
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