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secondary 4 | A Maths
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Help for q6 please. I don't know how to solve if I can't substitute x=3, -3, 0
Date Posted: 5 years ago
Views: 222
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I suspect that there is a flaw with the question for the integral part.
Date Posted:
5 years ago
Actually, when you go higher levels, you will learn that the integral of 1/x is actually ln (modulus x). This negates the effect of the issue faced in the question.
For your syllabus, there is no need to write out the modulus.
For your syllabus, there is no need to write out the modulus.
thank you!
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This post is to follow up on my comment above.
Date Posted:
5 years ago
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Here is the working had I used the modulus version.
Date Posted:
5 years ago
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